import java.util.Arrays;

import java.util.Scanner;

public class Main {

public static void main(String[] args) {

  Scanner in = new Scanner(System.in);

  int t = in.nextInt();

  while (t != 0) {

     int n = in.nextInt();

     int m = in.nextInt();

     long[] w = new long[n];

     for (int j = 0; j < w.length; j++) {

        w[j] = in.nextLong();

     }

     long[] x = new long[m];

     for (int k = 0; k < x.length; k++) {

        x[k] = in.nextLong();

     }

     for (int l = 0; l < w.length; l++) {

        for (int o = 0; o < x.length; o++) {

           if (w[l] == x[o]) {

              w[l] = 0;

           }

        }

     }

     Arrays.sort(w);

     for (int r = 0; r < w.length; r++) {

        if (w[r] != 0) {

           System.out.print(w[r] + ",");

        }

     }

     System.out.print("\b");

     System.out.println();

     t--;

  }

}

}

don't use "\b"

use StringBuilder class, and if you have answer, delete last char

        Arrays.sort(w);
        int flag = 0;
        StringBuilder sb = new StringBuilder();

        for (int r = 0; r < w.length; r++) {

            if (w[r] != 0) {
                flag = 1;
                sb.append(w[r]).append(",");
            }

        }
        if (flag == 1) {
            sb.delete(sb.length() - 1, sb.length());
        }

        System.out.println(sb.toString());

        t--;

thank you so much! but why we can't use "\b" while that give us same result?

M.Khooryani said:

don't use "\b"

use StringBuilder class, and if you have answer, delete last char

        Arrays.sort(w);
        int flag = 0;
        StringBuilder sb = new StringBuilder();

        for (int r = 0; r < w.length; r++) {

            if (w[r] != 0) {
                flag = 1;
                sb.append(w[r]).append(",");
            }

        }
        if (flag == 1) {
            sb.delete(sb.length() - 1, sb.length());
        }

        System.out.println(sb.toString());

        t--;

No, they aren't same

'\b' is a char

your answer and correct answer differs in length

for example:

    int length1 = "abc\b".length();
    int length2 = "ab".length();
    System.out.println(length1 + " " + length2);

output:

    4 2

Nima Mrd said:

thank you so much! but why we can't use "\b" while that give us same result?

M.Khooryani said:

don't use "\b"

use StringBuilder class, and if you have answer, delete last char

        Arrays.sort(w);
        int flag = 0;
        StringBuilder sb = new StringBuilder();

        for (int r = 0; r < w.length; r++) {

            if (w[r] != 0) {
                flag = 1;
                sb.append(w[r]).append(",");
            }

        }
        if (flag == 1) {
            sb.delete(sb.length() - 1, sb.length());
        }

        System.out.println(sb.toString());

        t--;

oh!! you're right! thx my friend ♥

M.Khooryani said:

No, they aren't same

'\b' is a char

your answer and correct answer differs in length

for example:

    int length1 = "abc\b".length();
    int length2 = "ab".length();
    System.out.println(length1 + " " + length2);

output:

    4 2

Nima Mrd said:

thank you so much! but why we can't use "\b" while that give us same result?

M.Khooryani said:

don't use "\b"

use StringBuilder class, and if you have answer, delete last char

        Arrays.sort(w);
        int flag = 0;
        StringBuilder sb = new StringBuilder();

        for (int r = 0; r < w.length; r++) {

            if (w[r] != 0) {
                flag = 1;
                sb.append(w[r]).append(",");
            }

        }
        if (flag == 1) {
            sb.delete(sb.length() - 1, sb.length());
        }

        System.out.println(sb.toString());

        t--;